Showing posts with label Admission. Show all posts
Showing posts with label Admission. Show all posts

Thursday, October 15, 2009

Crack competitions with Vedic math - IV | Transpose and Apply

Hi,

Once again, in my last article I have described the third formula of Vedic mathematics.

Now today in this article I will explain the fourth formula of Vedic mathematics.

The Fourth formula is-

“Transpose and Apply”

The term Parāvartya Yojayet this means “Transpose and apply”.

In this term they provide an easiest way to solve the polynomial division.

So let’s start - here you can see 4 simple steps for polynomial division

We take an example for this formula -

Divide x3 + 7x2 + 6x + 5 by x – 2.

i.) x3 divided by x gives us x2 which is therefore the first term of the quotient

x3 7x2 6x 5

x 2

+ + +

−

Q = x2 + ….

ii.) x2 × –2 = –2x2 but we have 7x2 in the divident. This means that we have to get 9x2 more. This must result from the multiplication of x by 9x. Hence the 2nd term of the divisor must be 9x

x3 7x2 6x 5

x 2

+ + +

−

Q = x2 + 9x +….

iii.) As for the third term we already have –2 × 9x = –18x. But we have 6x in the dividend. We must therefore get an additional 24x. Thus can only come in by the multiplication of x by 24. This is the third term of the quotient.

Q = x2 + 9x + 24

iv.) Now the last term of the quotient multiplied by – 2 gives us – 48. But the absolute term in the dividend is 5. We have therefore to get an additional 53 from some where. But there is no further term left in the dividend.

This means that the 53 will remain as the remainder

Q = x2 + 9x + 24 and R = 53.21

Further I will explain the next formula of Vedic math.

Tuesday, September 29, 2009

Crack competitions with Vedic math - IV | Vertically and Cross-wise

Hi,
Once again, I know everyone enjoying the great techniques of Vedic math with me. It is a great way to remove the irritation of math puzzles. Only keep formulas in his mind and get benefit of it.
In my last article I had described the second formula of Vedic mathematics.

Now in this article I will explain the third formula of Vedic mathematics.

The third formula is-

“VERTICALLY AND CROSS-WISE”

This method is a great way to find the multiplication of a small or bigger number
For example-

We take

8 X 9

Now we try to find the result of this multiplication with fastest Vedic mathematics.

No 8 is 2 below from 10
And no 9 is 1 below from 10

Now figure is like –






In this figure we subtract cross wise 8 -1 = 7 OR 9 – 2 = 7
And multiply vertically 2 X 1 = 2

So the final figure will look like –






So the final answer will be 72
You can see how it is easy to multiply

Further I will explain the next formula of Vedic math.

Wednesday, September 23, 2009

Crack competitions with Vedic math - III | All from 9 and the last from 10.

In my last article I have describe the first formula of Vedic mathematics. I hope all of you enjoy it.

Now let’s start to make the continuity, today I will explain the second formula of Vedic mathematics.

The Second formula is-

“ALL FROM 9 AND THE LAST FROM 10”

This method is always works for subtractions from numbers consisting of a 1 followed by noughts: 100; 1000; 10,000 etc.

For example-

1000 – 283

Now we solve this subtraction with fastest Vedic mathematics.

No 283 contains 3 digits – 2, 8 and 3.

Subtract each figure from 9 but the last figure (3) subtracted by 10.

Like-

9 – 2 = 7

9 – 8 = 1

10 – 3 = 7

1000 – 283 = 717

So final answer will be-

1000 – 283 = 717

Stay tuned up, further I will describe the 3rd formula of Vedic Mathematics.

Tuesday, September 22, 2009

Crack competitions with Vedic math - II | By One more than the One Before.

In my last article I have told about the origin and 16 sutras of Vedic mathematics.

So let’s start to play and solve math puzzles and calculation with some simple steps-

The first formula is-

“BY ONE MORE THAN THE ONE BEFORE.”

Through this method we can get the square amount of any no who end with 5

For example-

If we take 65 we take it because the 65 end with 5.

So

652 Means 65 X 65

The answer is always end with 25 it is fixed in this method so the last part of the answer will be 25

For get the first part of the answer-

The first part is the first number, 6, multiplied by the number "one more", which are 7:

6 X 7 = 42

So first part of the answer will be 42

Merge the first part and second part of the answer

4225

So final answer will be-

652 = 65 X 65

= 4225

Answer is 4225


Stay tuned up for further formulas of Vedic Mathematics.